Mathematical Operations on Whole Numbers up to 100,000
Primary 4 · Mathematics
Mathematical Operations on Whole Numbers up to 100,000
Lesson 5 of 5
35 min
Let's begin
Mugisha's big brother takes a moto to work. Each ride costs 1 200 Frw, and last month he took 23 rides. How much did he spend? Adding 1 200 twenty-three times would take a long time. Multiplication is the quick way.
When you multiply by 10, every digit moves one place to the left and a 0 fills the ones place: 345 × 10 = 3 450. Multiply by 100 and the digits move two places: 345 × 100 = 34 500.
Break the big number into its place values, multiply each part, then add the parts. These parts are called partial products.
2 347 × 6:
12 000 + 1 800 + 240 + 42 = 14 082. The column method does the same steps, starting with the ones and carrying.
Split the two-digit number into tens and ones. For the moto rides, 1 200 × 23:
24 000 + 3 600 = 27 600 Frw. That is what Mugisha's brother spent.
Four friends share 8 436 Frw equally. Work out 8 436 ÷ 4 by splitting 8 436 into parts that are easy to share:
2 000 + 100 + 9 = 2 109 Frw each. These parts are called partial quotients.
Work out 9 275 ÷ 6. Divide from the left, one place at a time:
So 9 275 ÷ 6 = 1 545 remainder 5. Check: 1 545 × 6 = 9 270, and 9 270 + 5 = 9 275.
250 pupils visit Lake Kivu, and each boat carries 6 pupils. 250 ÷ 6 = 41 remainder 4. Forty-one boats are full, but 4 pupils are still on the shore! They need one more boat, so the school needs 42 boats. Always ask what the remainder means in the story.
Practise: open the Arithmetic simulation and play the Multiply and Divide games to make your times tables quick. Quick tables make big sums easy.
Tip
Break it, then build it. Break a big number into thousands, hundreds, tens and ones. Multiply or divide each part, then add the parts back together.
Work each one in your exercise book first. Then tap Show answer to check.
3 406 × 7
Answer: 23 842 (21 000 + 2 800 + 42)
425 × 24
Answer: 10 200 (425 × 20 = 8 500 and 425 × 4 = 1 700)
9 648 ÷ 8
Answer: 1 206
7 453 ÷ 5
Answer: 1 490 remainder 3
A school buys 18 footballs at 4 500 Frw each. How much does it pay?
Answer: 81 000 Frw
What you learned today
Sources and credits
The stories, Rwandan worked examples, diagrams and practice questions were written by Ganzaa.
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