Inorganic Salts: Properties, Preparation and Identification of Ions
Senior 2 · Chemistry
Inorganic Salts: Properties, Preparation and Identification of Ions
Lesson 5 of 5
25 min
Water-testing laboratories check drinking water for dissolved ions. Agricultural inspectors check that a bag labelled "potassium chloride" really contains potassium and chloride. Forensic scientists identify unknown white powders. All of them rely on qualitative analysis: simple tests that show which ions a substance contains, by a colour, a precipitate or a gas.
By the end of this lesson you will be able to carry out and interpret flame tests, the sodium hydroxide and ammonia tests for cations, and the tests for carbonate, chloride, sulfate and nitrate ions.
Some metal ions give a characteristic colour to a flame.
| Ion | Flame colour |
|---|---|
| Na+ | Bright yellow-orange (lasts a long time) |
| K+ | Lilac (pale purple) |
| Ca2+ | Brick-red (orange-red) |
| Cu2+ | Blue-green |
| Li+ | Crimson (deep red) |
| Ba2+ | Pale (apple) green |
Dissolve the sample in distilled water. Add a few drops of sodium hydroxide solution, then add it in excess (until no further change). Repeat with a fresh sample using aqueous ammonia. Most metal hydroxides are insoluble, so a precipitate forms, and its colour and behaviour in excess identify the ion.
| Cation | Sodium hydroxide: a few drops | Sodium hydroxide: excess | Aqueous ammonia: a few drops | Aqueous ammonia: excess |
|---|---|---|---|---|
| Cu2+ | Pale blue precipitate | Insoluble | Pale blue precipitate | Dissolves to give a deep blue solution |
| Fe2+ | Green precipitate (turns brown on standing) | Insoluble | Green precipitate | Insoluble |
| Fe3+ | Red-brown precipitate | Insoluble | Red-brown precipitate | Insoluble |
| Zn2+ | White precipitate | Dissolves (colourless solution) | White precipitate | Dissolves (colourless solution) |
| Al3+ | White precipitate | Dissolves | White precipitate | Insoluble |
| Pb2+ | White precipitate | Dissolves | White precipitate | Insoluble |
| Ca2+ | White precipitate | Insoluble | No precipitate (or very slight) | No precipitate |
| NH4+ | No precipitate. On warming with sodium hydroxide, ammonia gas is given off: it has a sharp smell and turns damp red litmus paper blue. | |||
Al3+ and Pb2+ give the same results with both reagents. To tell them apart, add potassium iodide solution: Pb2+ gives a bright yellow precipitate of lead(II) iodide, and Al3+ gives none.
The precipitates are hydroxides, for example:
Cu2+(aq) + 2OH−(aq) → Cu(OH)2(s)
Fe3+(aq) + 3OH−(aq) → Fe(OH)3(s)
NH4+(aq) + OH−(aq) → NH3(g) + H2O(l)
Carbonate, CO32−. Add dilute hydrochloric acid. Effervescence (fizzing) shows a gas; bubble it through limewater. If the limewater turns milky, the gas is carbon dioxide and the sample contains carbonate.
CO32− + 2H+(aq) → H2O(l) + CO2(g) then Ca(OH)2(aq) + CO2(g) → CaCO3(s) + H2O(l)
Chloride, Cl−. Acidify the solution with dilute nitric acid, then add silver nitrate solution. A white precipitate of silver chloride shows chloride. (Bromide gives a cream precipitate and iodide a yellow one.)
Ag+(aq) + Cl−(aq) → AgCl(s)
Sulfate, SO42−. Acidify with dilute hydrochloric acid (or nitric acid), then add barium chloride (or barium nitrate) solution. A white precipitate of barium sulfate shows sulfate.
Ba2+(aq) + SO42−(aq) → BaSO4(s)
Why acidify first? Carbonate ions also give white precipitates with silver ions and with barium ions. The acid destroys any carbonate (as carbon dioxide) first, so a white precipitate can only mean chloride or sulfate. Never acidify with hydrochloric acid before a chloride test: it would add the very chloride ions you are testing for.
Nitrate, NO3−. The brown ring test (a teacher demonstration, because it uses concentrated acid): add freshly made iron(II) sulfate solution to the sample, then carefully pour concentrated sulfuric acid down the side of the tilted test tube so that it forms a layer underneath. A brown ring where the two layers meet shows nitrate. An alternative is to warm the sample with sodium hydroxide solution and a little aluminium foil: nitrate is reduced to ammonia, which turns damp red litmus blue.
A blue solid dissolves in water. With sodium hydroxide it gives a pale blue precipitate that does not dissolve in excess. After acidifying with dilute hydrochloric acid, barium chloride gives a white precipitate. Identify the salt.
Solution. The pale blue hydroxide, insoluble in excess sodium hydroxide, shows Cu2+. The white precipitate with acidified barium chloride shows SO42−. The salt is copper(II) sulfate.
A white powder gives a lilac flame. It fizzes with dilute hydrochloric acid, and the gas turns limewater milky. Identify it.
Solution. Lilac flame: K+. Carbon dioxide with acid: CO32−. The salt is potassium carbonate, K2CO3.

Tip
Colours first: blue = copper(II), green = iron(II), red-brown ("rusty") = iron(III).
Then the white precipitates: zinc dissolves in excess of both reagents; aluminium and lead(II) dissolve only in excess sodium hydroxide; calcium dissolves in neither and gives nothing with ammonia.
Anions: "Acid first, then the silver or barium."
Try each item before you read the solution.
A solution gives a white precipitate with a few drops of sodium hydroxide, which dissolves in excess. With aqueous ammonia it gives a white precipitate that does not dissolve in excess. Which two cations could be present, and how could you tell them apart?
Solution: Al3+ or Pb2+. Add potassium iodide solution: a yellow precipitate shows Pb2+; no precipitate shows Al3+.
A green solution gives a green precipitate with sodium hydroxide that slowly turns brown at the surface. Name the cation and explain the colour change.
Solution: Iron(II), Fe2+. The green iron(II) hydroxide is slowly oxidised by oxygen in the air to red-brown iron(III) hydroxide.
How would you show that a fertiliser contains ammonium ions?
Solution: Warm a sample with sodium hydroxide solution. If a gas with a sharp smell is given off that turns damp red litmus paper blue, it is ammonia, so ammonium ions are present: NH4+(aq) + OH−(aq) → NH3(g) + H2O(l).
Byiringiro adds silver nitrate to a solution without acidifying it, sees a white precipitate and concludes that chloride is present. Why might he be wrong?
Solution: Carbonate ions also give a white precipitate (silver carbonate) with silver nitrate. He should first add dilute nitric acid to remove any carbonate; only a white precipitate that forms after acidifying proves chloride.
Summary
Sources and credits
This lesson adapts CC BY-SA material and is shared under CC BY-SA 4.0.