Wave and Particle Nature of Light
Senior 5 · Physics
Wave and Particle Nature of Light
Lesson 4 of 5
25 min
In 1922 and 1923 Arthur Compton, at Washington University in St Louis, fired X-rays of a single wavelength at a block of graphite and measured the wavelengths of the X-rays scattered at different angles. Classical wave theory says that the electrons in the graphite should simply be shaken at the frequency of the incoming wave and re-radiate at that same frequency. Instead, Compton found two lines in the scattered radiation: one at the original wavelength and one at a longer wavelength, and the shift grew with the scattering angle. He explained it by treating the X-ray as a particle that bounces off an electron like one billiard ball off another, carrying momentum as well as energy. The Compton effect was the evidence that convinced most physicists that photons are real.

A photon of wavelength has momentum and energy . It strikes a free electron at rest (an outer electron of carbon is so loosely bound that it can be treated as free). The photon scatters at angle with a longer wavelength , and the electron recoils at angle .
The recoiling electron can be fast, so its energy must be written relativistically (you will meet this in Unit 10): its total energy and momentum satisfy , where is the electron's rest mass.
Momentum is conserved (a vector equation): . Squaring, with the cosine rule,
Energy is conserved: , so . Squaring,
Put (1) into and set it equal to (2). The terms , and cancel, leaving
Divide both sides by : . Since ,
The shift depends only on the angle, not on the wavelength or on the scattering material. The constant m is the Compton wavelength of the electron. The shift is zero at , equals at 90° and reaches its maximum, pm, when the photon bounces straight back.
The unshifted line comes from photons scattered by tightly bound inner electrons. Then the whole carbon atom recoils, and its mass is about 22 000 times the electron's, so the shift is far too small to see.
Definition
The Compton effect is the increase in the wavelength of X-rays or gamma rays when they are scattered by loosely bound electrons: . The Compton wavelength of the electron is . Example: at the shift is pm.
Worked example 1: scattering at 90°
X-rays of wavelength 71.1 pm are scattered through 90° by a free electron at rest (the diagram above). Find (a) the scattered wavelength, (b) the energies of the incident and scattered photons in keV, (c) the kinetic energy of the recoil electron and (d) its direction.
Solution
(a) pm, so pm.
(b) Using : keV and keV.
(c) By energy conservation, keV.
(d) Along the original direction the electron's momentum is ; at right angles it must cancel the scattered photon's . So , below the original direction.
Worked example 2: a gamma ray bounced straight back
A gamma-ray photon of energy 0.662 MeV is scattered through 180° by an electron. Find the energy of the scattered photon and the kinetic energy given to the electron. ( MeV.)
Solution
Writing the Compton formula in terms of energy (): . With :
The electron receives MeV, the most it can get in a single Compton collision. Radiation detectors show a sharp edge in their energy spectra at exactly this value.
A photon passing through matter usually travels some distance untouched and then interacts in one event. Four processes matter:
| Process | What happens | Energy condition |
|---|---|---|
| Photoelectric absorption | The photon is absorbed completely by a bound electron, which is ejected with energy | Most likely at low energies and in high- materials such as lead |
| Compton scattering | The photon gives part of its energy to a loosely bound electron and continues with a longer wavelength | Dominant at medium energies |
| Pair production | Near a nucleus, the photon disappears and an electron and a positron (its antiparticle) are created | Needs MeV |
| Pair annihilation (the reverse) | An electron and a positron meet and vanish, producing two photons | Each photon has 0.511 MeV if the pair was at rest |
Pair production turns energy into mass. The photon must supply the rest energy of both particles, , and any extra becomes their kinetic energy:
It cannot happen in empty space: a single photon cannot turn into two particles while conserving both energy and momentum. A nearby nucleus takes up the spare momentum while taking almost no energy.
In annihilation of a pair at rest, the total momentum is zero, so two photons must be produced, moving in opposite directions with equal energy MeV. Hospital PET scanners detect exactly these back-to-back pairs of photons.
Definition
Pair production is the creation of a particle and its antiparticle (usually an electron and a positron) from a photon of energy at least MeV, in the field of a nucleus. Pair annihilation is the reverse: a particle and its antiparticle meet and are converted into photons. Example: a 1.50 MeV photon can make a pair with MeV of kinetic energy between them.
Worked example 3: thresholds and wavelengths
(a) Find the longest wavelength of a photon that can produce an electron–positron pair. (b) A 3.0 MeV photon produces a pair. Find the total kinetic energy of the pair. (c) Find the wavelength of each photon produced when an electron and a positron annihilate at rest.
Solution
(a) nm pm.
(b) MeV, shared between the electron and the positron.
(c) Each photon has 0.511 MeV, so nm pm, equal to the Compton wavelength of the electron, as it must be, since .
Warning
Compton is not photoelectric. In the photoelectric effect the photon is absorbed and disappears; in Compton scattering it survives with less energy. And the Compton shift does not depend on the incident wavelength, but the fractional shift does: that is why it is noticeable for X-rays and invisible for light.
Tip
Three numbers to remember: 2.43 pm (the Compton wavelength), 0.511 MeV (the electron's rest energy), 1.022 MeV (the pair-production threshold). The second is divided by the first, and the third is twice the second.
Compton Scattering, MIT OpenCourseWare (a lecture from MIT's quantum physics course 8.04). Watch how energy and momentum conservation are combined to derive the wavelength shift; the derivation matches the one above.
Practice
Key points
Sources and credits
Written by Ganzaa. The collision diagram (drawn to the angles of Worked example 1), the energy-range chart, the worked examples and the practice exercises are by Ganzaa.