Signals and Communication Systems
Senior 5 · Physics
Signals and Communication Systems
Lesson 3 of 4
25 min
Speech and music lie between about 20 Hz and 20 kHz. Could a radio station simply feed its microphone signal to an aerial? At 20 kHz the wavelength is km, and an efficient aerial must be a sizeable fraction of a wavelength, kilometres long. Worse, every station would broadcast in the same frequency band, and a receiver could not separate them. The solution is modulation: the audio signal is made to vary some property of a high-frequency carrier wave, and each station is given its own carrier frequency. An FM station at 100 MHz needs an aerial only about 1.5 m long, and dozens of stations share the air without interfering.
In AM, the amplitude of the carrier is made to follow the audio signal. For a carrier and an audio signal ,
The ratio is the modulation index. It must not exceed 1, or the envelope folds over and the audio is distorted (over-modulation).
Using , the AM wave is the sum of three sine waves:
Besides the carrier there are two side frequencies, and , each of amplitude . Real audio contains a range of frequencies up to , which produces two sidebands, and the bandwidth of the AM signal is
Since power is proportional to amplitude squared, the total power is , where is the carrier power. All the information is in the sidebands; the carrier itself carries none.
Definition
Modulation is varying a property (amplitude, frequency or phase) of a high-frequency carrier wave in step with the information signal. The modulation index of AM is . Sidebands are the bands of frequencies on either side of the carrier, , that carry the information. Example: a 1000 kHz carrier modulated by 3 kHz audio has side frequencies at 997 kHz and 1003 kHz.
Worked example 1: an AM signal
A carrier of frequency 1000 kHz and amplitude 10 V is amplitude-modulated by a 5.0 kHz tone of amplitude 6.0 V. Find (a) the modulation index, (b) the side frequencies and their amplitudes, (c) the bandwidth, (d) the fraction of the total power in the sidebands. (This is the spectrum drawn above.)
Solution
(a) .
(b) : 995 kHz and 1005 kHz, each of amplitude V.
(c) kHz.
(d) Sideband power total power , only 15%: AM wastes most of its power on the carrier.
In FM the amplitude of the carrier stays constant and its frequency is made to vary with the audio signal: louder sound swings the frequency further from , and higher-pitched sound swings it more often. The greatest change of frequency is the frequency deviation . The bandwidth needed is given approximately by Carson's rule:
Broadcast FM uses kHz and audio up to 15 kHz, so kHz; stations in the 87.5–108 MHz band are spaced 200 kHz apart. AM broadcasting in Africa and Europe uses channels only 9 kHz apart.
| AM | FM | |
|---|---|---|
| What varies | Carrier amplitude | Carrier frequency |
| Bandwidth of a broadcast station | About 9 kHz | About 180 kHz |
| Audio quality | Limited (audio up to about 4.5 kHz) | High (audio up to 15 kHz, stereo) |
| Noise | Most electrical noise changes amplitude, so it is heard | Receiver ignores amplitude changes, so much less noise |
| Usual band and range | Long and medium wave; ground wave, hundreds of km; short wave, worldwide | VHF; line of sight, tens of km |
| Equipment | Simpler and cheaper | More complex |
Digital data is carried by switching a property of the carrier between fixed values: its amplitude (ASK, amplitude-shift keying), its frequency (FSK) or its phase (PSK). Wi-Fi and 4G combine amplitude and phase steps (QAM), so that each symbol carries several bits at once.
For an aerial at height above flat ground on an Earth of radius , the distance to the horizon is found from Pythagoras: , and since ,
Worked example 2: the range of an FM transmitter
An FM aerial stands 100 m above the surrounding land. (a) How far away is its horizon? (b) How far can it reach a receiving aerial mounted 10 m high? ( m.) (c) Find the length of a half-wave dipole aerial for a 100 MHz station.
Solution
(a) m km.
(b) The receiving aerial has its own horizon, km, so the range is km over flat land. In hilly country hills block the path, which is why a broadcaster needs many hilltop transmitters to cover the whole of a country like Rwanda.
(c) m, so the dipole is m long.
Nearly every radio is a superheterodyne receiver. The mixer combines the incoming signal with a local oscillator whose frequency is set by the tuning dial, always a fixed amount above the wanted carrier. This shifts the chosen station to a fixed intermediate frequency (IF), where most of the amplification and filtering is done by circuits that never need retuning. The demodulator then recovers the audio.
Worked example 3: the local oscillator
An AM receiver with an IF of 455 kHz is tuned to a station at 1000 kHz. (a) What frequency must the local oscillator produce? (b) The mixer also responds to a second frequency, the image, that differs from the oscillator frequency by 455 kHz. Find it, and explain why the RF stage must be tuned.
Solution
(a) kHz.
(b) The mixer output contains the difference frequency . A station at kHz would also give 455 kHz. The tuned RF amplifier rejects this image before it reaches the mixer.
Warning
The AM bandwidth is twice the highest audio frequency, not the carrier frequency. A 1000 kHz station sending 4.5 kHz audio occupies 995.5–1004.5 kHz: 9 kHz wide. And over-modulation () distorts the audio and spreads the signal into neighbouring channels.
Tip
AM: Amplitude Moves. FM: Frequency Moves. For bandwidth, AM is ; FM adds the deviation: .
How Information Travels Wirelessly, MITK12Videos. Watch how a radio wave is made to carry information and how a receiver picks out one signal from many.
Practice
Key points
Sources and credits
Written by Ganzaa. The AM waveform and spectrum (drawn to scale for Worked example 1), the receiver diagram, the worked examples and the practice exercises are by Ganzaa.